//
// Created by IL-CH on 2024/6/13.
//
/**
若两个复数分别为：complex1 = real1 + imag1 i 和 complex2 = real2 + imag2 i，则

它们的和为：complex1 + complex2 = (real1 + real2) + (imag1 + imag2) i

它们的乘积为：complex1 * complex2 = (real1 * real2 - imag1 * imag2) + (real1 * imag2 + real2 * imag1) i

本题要求实现两个函数分别计算两个复数之和、两个复数之积。

函数接口定义：
void complex_add (double real1, double imag1, double real2, double imag2);
void complex_prod (double real1, double imag1, double real2, double imag2);
其中用户传入的参数为两个复数real1 + imag1 i 和real2 + imag2 i；函数complex_add和函数complex_prod应将计算结果的实部存放在全局变量result_real中、虚部存放在全局变量result_imag中。

裁判测试程序样例：
#include <stdio.h>

double result_real, result_imag;
void complex_add(double real1, double imag1, double real2, double imag2);
void complex_prod(double x1, double y1, double x2, double y2);

int main(void)
{
    double imag1, imag2, real1, real2;

    scanf("%lf %lf", &real1, &imag1);
    scanf("%lf %lf", &real2, &imag2);
    complex_add(real1, imag1, real2, imag2);
    printf("addition of complex is (%f)+(%f)i\n", result_real, result_imag);
    complex_prod(real1, imag1, real2, imag2);
    printf("product of complex is (%f)+(%f)i\n", result_real, result_imag);

    return 0;
}

请在这里填写答案
输入样例：
1 1
-2 3
输出样例：
addition of complex is (-1.000000)+(4.000000)i
product of complex is (-5.000000)+(1.000000)i

*/
#include <stdio.h>

double result_real, result_imag;
void complex_add(double real1, double imag1, double real2, double imag2);
void complex_prod(double x1, double y1, double x2, double y2);

int main(void)
{
    double imag1, imag2, real1, real2;

    scanf("%lf %lf", &real1, &imag1);
    scanf("%lf %lf", &real2, &imag2);
    complex_add(real1, imag1, real2, imag2);
    printf("addition of complex is (%f)+(%f)i\n", result_real, result_imag);
    complex_prod(real1, imag1, real2, imag2);
    printf("product of complex is (%f)+(%f)i\n", result_real, result_imag);

    return 0;
}

/* 请在这里填写答案 */
void complex_add(double real1, double imag1, double real2, double imag2)
{
    result_real = real1 + real2;
    result_imag = imag1 + imag2;
}

void complex_prod(double x1, double y1, double x2, double y2)
{
    result_real = x1 * x2 - y1 * y2;
    result_imag = x1 * y2 + x2 * y1;
}